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Slide 1 I ’ d like to introduce a question of Ontario Canada grade 12 physics for university preparation, coded as SPH4U. Khoi spins to throw a rock. The rock’s weight, rope’s length, velocity angle and height of the rock, the tension in the rope when he let the rock go are all known. The question asks the distance between the points where the rock is let go and where it hits the ground.   Slide 2 This is figure one. O is the point where rock is let go. Line OH is horizontal. The angle between velocity V and OH is 30º. The angle between the rope tension T and the horizontal line OH is α. The rock’s weight is G which is 2g newtons. The small g is the acceleration of gravity. The rock weight G and rope tension T together form the centripetal force F. So F is the resultant of G and T.   Slide 3 This is the legend of figure one.   (Show slide 2) Since force F is the centripetal force when the rock is let go, force F is perpendicular to velocity V. So the angle between force F...

  Slide 1 This is a simply-supported beam. X is the beam axis before deformation. This curve is its axis after deformation under force P. O, C, C1 are points on the beam axis, and C1 is the position of point C after force P is exerted. Point O is the origin of the coordinate system.  The horizontal coordinate of Point C is x. W(x) is the deflection at point C, which equals to the length of line CC1. If the beam at point C moves downward under force P, the deflection at C w(x) is positive. Otherwise, negative. θ(x) is the rotation angle of beam cross section at point C under force P.  If the beam cross section at point C rotates clockwise under force P , rotation angle of beam cross section at point C θ(x) is positive, otherwise negative. Before force P exerts, the cross section at point C is vertical. Under force P, it’s slanted. The section turns in this direction. That’s clockwise. So the rotation angle of beam cross section at point C θ(x) is positive.   Slide 2 T...

  email: about Concrete Design Handbook's Example 2.3e Several lines omitted here. I have some question with Example 2.3 of Concrete Design Handbook, 3rd edition, fourth printing December 2010. In page 2-13, Example 2.3, it is assumed that the compression steel is yielding, and the moment resistance is calculated accordingly. I disagree with the assumption. I find that the compression steel does not yield, and with more compression reinforcement, compression steel's stress is getting lower and further from yielding stress. The attached is my calculation. Would you please do me a favor to give me some advice about my calculation? Several lines omitted here. Attachment of the email about the calculation mentioned in the email: Concrete Design Handbook, 3 rd edition, fourth printing December 2010 Page 2-13, Example 2.3 – Analysis of a Rectangular Beam with Tension and Compression Reinforcement Calculate the flexural resistance of the beam shown in the figure.     d = 3...

My academic requirement interview s  of professional engineer application in Ontario Canada   I would like to talk about my two interviews of academic requirement of professional engineer application in Ontario Canada. I applied for the license of professional engineer in Ontario after I had immigrated to Canada and worked in a labor job for several months. The application is managed by Professional Engineers Ontario, that is PEO for  short. After submitting the docume n ts required  by PEO, I was informed to prepare for several technical exams or an interview. To speed up the application, I applied for the interview and prepared for the exams at the same time. Several weeks later, I attended my first interview. Upon entering the office, I found two interviewers sitting beside the big table, one to ask questions, the other one to record the interview, and also ask questions. My discipline  is structural engineering of civil engineering. Interviewees  were p...

  about Concrete Design Handbook's Example 2.3e 此处省略 I have some question with Example 2.3 of Concrete Design Handbook, 3rd edition, fourth printing December 2010. In page 2-13, Example 2.3, it is assumed that the compression steel is yielding, and the moment resistance is calculated accordingly. I disagree with the assumption. I find that the compression steel does not yield, and with more compression reinforcement, compression steel's stress is getting lower and further from yielding stress. The attached is my calculation. Would you please do me a favor to give me some advice about my calculation? 此处省略 下面是电邮附件（计算过程） Concrete Design Handbook, 3 rd edition, fourth printing December 2010 Page 2-13, Example 2.3 – Analysis of a Rectangular Beam with Tension and Compression Reinforcement Calculate the flexural resistance of the beam shown in the figure.     d = 330mm, = 65mm, = 30MPa, f y = 400Mpa, E s = 2 X10 5 MPa, Ec =  4500 = 4500 = 24647 MPa = 0.85 – 0...