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前面说了，幺叔酷爱打架。小时候，乡下经常放露天电影，都是各村出钱请的镇上的电影放映队。幺叔几乎场场不拉。如果以为他是影迷就错了，他自己就是地地道道的演员，演的全武行，而且绝对逼真如假包换。他看电影就为打架。露天电影，人挤人人挨人，而且很多荷尔蒙爆棚的小伙子，年轻气盛，七個不平,八個不忿的，很容易擦枪走火，更何况还有那么多小媳妇大姑娘，谁都想在她们面前露一脸，因此这里是打架的理想温床，也是幺叔魂牵梦绕的战场。他几乎每场必打，经常在我面前炫耀他的战绩。一次他孤身对七八人，他采取运动战，边跑边打，注意这里说的跑可不是逃跑，那不是幺叔这种酷爱打架的人的做派，他的跑是寻找战机，找到对方破绽迅猛出击，力图一击ko，他说他把那帮家伙全打趴下了。还有一次遇到一个比他力气还大的，居然把他按倒在地，这是他遇到的绝无仅有的情况，所以印象深刻，他跟我谈起时还夸赞对手。既然力敌不行，那就智取，他一手电砸过去，对方脑袋开花，马上结出了他的胜利果实。 记得有一年大学暑假父亲派我照看西瓜地。瓜地离村子较远，在瓜地旁边用帆布搭了个棚子，里面有蚊帐，我晚上就睡在里面。幺叔晚上也去，但他不睡，他有更刺激的事情，哪能睡得着。每到天黑，幺叔就出动了，像猫捉老鼠一样兴奋，马不停蹄到处寻找战机，不光我们家的瓜地，捎带手把旁边一大片瓜地都照看了，根本用不着别人谢他。白天跟我炫耀战果，把多少人吓得丢盔弃甲屁滚尿流。有他老人家罩着，寡人无忧矣。我每天按时睡觉按时起床，跟在家里无异，根本不关心晚上瓜地的事情。白天看一大本书，逐道解答里面的习题，书里有答案，完了核对正误，做对为止，瓜看完了题也做完了，每天过得很充实。远处瓜地有位河南老乡是我们请来指导种瓜的师傅，听说以前是国民党的营长，须髯飘飘仙风道骨，每天早晨远远看着他迎着朝阳巡视瓜地，然后做我的习题，注意力高度集中，完全忘了照瓜的事情。傍晚看着他踏着夕阳检查一个个西瓜，然后猫腰进我的金顶大帐呼呼大睡，外面自有兢兢业业乐此不疲的幺叔替我守夜。 小时候他经常教唆我打架，总说，莫怕有幺叔。现在想来他其实主要想让我给他创造战机，我去打架，如果对方家长护孩子，他的机会不就来了？但我怕我爸，我很少给他这种机会，让他老人家失望了。 但有次我倒给他创造了绝佳机会。那次我在水塘埂上玩，村里有个小孩在塘埂的沟里玩泥巴把泥巴丢到了我身上，我们发生争吵，他奶奶过来帮他，骂我是地主家伙之类侮辱...

 近来为疫情所困，闲来无事，看见很多人在油管上做视频，也弄了几个上去凑凑热闹，不料看起来容易做起来难，几个视频下去没有多少动静。同学帮忙出主意，叫我去论坛逛逛，听人劝吃饱饭，上去注了册，还在审核中，也不知道要审到么时候。网上有人建议去脸书试试，好不容易混进了两个群组，一发帖子就被脸书打脸，脸书说，虽然你没有恶意，但你的帖子被拒。我小心翼翼怕冒犯脸书大人，帖子中只斗胆提了我油管中的一个视频，说我是认真做的，里面的东西大部分是我自己想到的，当时去多伦多图书馆查了相关书籍，没有发现相同内容，希望能对亲爱的观众有那么一点点帮助。       也有同学叫我搞点大众话题。现在离婚率这么高，而婚姻又这么重要，我想就婚姻吧。在网上上下求索，发现戈特曼名气大，在他的书中婚姻幸福的七条原则最为有名，在多伦多图书馆预约了好长时间才到手，在图书馆又没查到中文版，心想就它了。因为一次只能借21天，这么热门的书又没法续借，还了之后难得借到，赶紧拿回家抓紧看，认真看了几天，边看边做笔记，突然犯嘀咕，不会有人也惦记上了这本书，捷足先登了吧？上网一查，果然浙江人民出版社已经出了中文版，油管上也有人谈了这本书。得了，这几天白忙活了。接着又想起来我以前看过一些苏曼殊，李叔同，张爱玲等民国人物的书，可不可以蹭一下这些大腕的热度呢？一查油管，也有不少。 这几板斧下去莫说杨正将军了，就连个虾兵蟹将都冇砍到。怎么办，事到如今好为难。思来想去，主意打到了老祖宗头上。我先辈的故事都是我父母耳提面授，有的是我亲眼所见，别人无法与闻，也无法和我抢这个题材。唯一的顾虑是涉及先人隐私，而他们又都已仙逝，没办法征得他们同意。这时我想起先父曾经跟我有约，我们俩，他图名我图利，就是他将来负责为我赚钱，我负责为他挣面子。我想我虽没给他挣到城门大的脸面，但一般小门小户的门面还是挣到过的。我是全镇第一名进的县高中，文革后全村第一个上的大学，全村第一个读的博士。但我父亲却未能履约，他在我大学毕业前一年年底瘫痪，这之前他已买好机器设备，准备大干一场。我们是农村的，没有公费医疗，当时所有治疗费用都得自己出，而我们家绝大部分经济来源都靠他，他这一倒，用村里人的话说就是房子顶梁柱垮了。本来我们可以互相促进的，我可以用他的钱打点工作中的关系，他可以用我的名帮他抬高声誉赚更多的钱。我们好比两条腿，本来...

Slide 1 I ’ d like to introduce a question of Ontario Canada grade 12 physics for university preparation, coded as SPH4U. Khoi spins to throw a rock. The rock’s weight, rope’s length, velocity angle and height of the rock, the tension in the rope when he let the rock go are all known. The question asks the distance between the points where the rock is let go and where it hits the ground.   Slide 2 This is figure one. O is the point where rock is let go. Line OH is horizontal. The angle between velocity V and OH is 30º. The angle between the rope tension T and the horizontal line OH is α. The rock’s weight is G which is 2g newtons. The small g is the acceleration of gravity. The rock weight G and rope tension T together form the centripetal force F. So F is the resultant of G and T.   Slide 3 This is the legend of figure one.   (Show slide 2) Since force F is the centripetal force when the rock is let go, force F is perpendicular to velocity V. So the angle between force F...

  Slide 1 This is a simply-supported beam. X is the beam axis before deformation. This curve is its axis after deformation under force P. O, C, C1 are points on the beam axis, and C1 is the position of point C after force P is exerted. Point O is the origin of the coordinate system.  The horizontal coordinate of Point C is x. W(x) is the deflection at point C, which equals to the length of line CC1. If the beam at point C moves downward under force P, the deflection at C w(x) is positive. Otherwise, negative. θ(x) is the rotation angle of beam cross section at point C under force P.  If the beam cross section at point C rotates clockwise under force P , rotation angle of beam cross section at point C θ(x) is positive, otherwise negative. Before force P exerts, the cross section at point C is vertical. Under force P, it’s slanted. The section turns in this direction. That’s clockwise. So the rotation angle of beam cross section at point C θ(x) is positive.   Slide 2 T...

  email: about Concrete Design Handbook's Example 2.3e Several lines omitted here. I have some question with Example 2.3 of Concrete Design Handbook, 3rd edition, fourth printing December 2010. In page 2-13, Example 2.3, it is assumed that the compression steel is yielding, and the moment resistance is calculated accordingly. I disagree with the assumption. I find that the compression steel does not yield, and with more compression reinforcement, compression steel's stress is getting lower and further from yielding stress. The attached is my calculation. Would you please do me a favor to give me some advice about my calculation? Several lines omitted here. Attachment of the email about the calculation mentioned in the email: Concrete Design Handbook, 3 rd edition, fourth printing December 2010 Page 2-13, Example 2.3 – Analysis of a Rectangular Beam with Tension and Compression Reinforcement Calculate the flexural resistance of the beam shown in the figure.     d = 3...

My academic requirement interview s  of professional engineer application in Ontario Canada   I would like to talk about my two interviews of academic requirement of professional engineer application in Ontario Canada. I applied for the license of professional engineer in Ontario after I had immigrated to Canada and worked in a labor job for several months. The application is managed by Professional Engineers Ontario, that is PEO for  short. After submitting the docume n ts required  by PEO, I was informed to prepare for several technical exams or an interview. To speed up the application, I applied for the interview and prepared for the exams at the same time. Several weeks later, I attended my first interview. Upon entering the office, I found two interviewers sitting beside the big table, one to ask questions, the other one to record the interview, and also ask questions. My discipline  is structural engineering of civil engineering. Interviewees  were p...